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a circle has the equation (x-2)^2+(y+4)^2=169. which of the following is the center of the circle(2,4) (2,4), (-2,4) (-2,4), (2,-4) (2,-4), (-2,-4)? - Answers

The answer is (2-4)



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a circle has the equation (x-2)^2+(y+4)^2=169. which of the following is the center of the circle(2,4) (2,4), (-2,4) (-2,4), (2,-4) (2,-4), (-2,-4)? - Answers

https://math.answers.com/algebra/A-circle-has-the-equation-x-2^2+y+4^2=169-which-of-the-following-is-the-center-of-the-circle24-24-24-24-2-4-2-4-2-4

The answer is (2-4)



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a circle has the equation (x-2)^2+(y+4)^2=169. which of the following is the center of the circle(2,4) (2,4), (-2,4) (-2,4), (2,-4) (2,-4), (-2,-4)? - Answers

The answer is (2-4)

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