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Can you take the square root of a negative number? - Answers
NO!!!! sqrt(-n) ????? However, -n X -n = (+)n^2 Sqrt(n^2) = either -n or (+)n , because either -n X -n = (+)n^2 or n x n = n^2 However, sqrt(-n) takes us into IMAGINARY numbers. sqrt(-n) = sqrt( -1 x n) = sqrt(-1) X sqrt(n) .The sqrt(-1) is mathemtically unresolved and is given the symbol 'i' (small / lower case letter 'i'. The sqrt(n) .being positive can be found.
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Can you take the square root of a negative number? - Answers
NO!!!! sqrt(-n) ????? However, -n X -n = (+)n^2 Sqrt(n^2) = either -n or (+)n , because either -n X -n = (+)n^2 or n x n = n^2 However, sqrt(-n) takes us into IMAGINARY numbers. sqrt(-n) = sqrt( -1 x n) = sqrt(-1) X sqrt(n) .The sqrt(-1) is mathemtically unresolved and is given the symbol 'i' (small / lower case letter 'i'. The sqrt(n) .being positive can be found.
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Can you take the square root of a negative number? - Answers
NO!!!! sqrt(-n) ????? However, -n X -n = (+)n^2 Sqrt(n^2) = either -n or (+)n , because either -n X -n = (+)n^2 or n x n = n^2 However, sqrt(-n) takes us into IMAGINARY numbers. sqrt(-n) = sqrt( -1 x n) = sqrt(-1) X sqrt(n) .The sqrt(-1) is mathemtically unresolved and is given the symbol 'i' (small / lower case letter 'i'. The sqrt(n) .being positive can be found.
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