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Find two consecutive odd numbers whose product is 399? - Answers

If one of the numbers is x, then the other number is x + 2. So, x(x + 2) = 399 x^2 + 2x = 399 Complete the square by adding 1 at both sides ; x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2 (x + 1)^2 = 400 x + 1 = (+ & - )(square root of 400) subtract 1 to both sides x = -1 (+ & -) 20 x = -1 + 20 or x = -1 - 20 x = 19 or x = -21 So, x + 2 = 19 + 2 = 21 or x + 2 = - 21 + 2 = - 19 Thus the numbers are: 19 and 21 or -19 and - 21 Check: (19)(21) = 399 (-19)(-21) = 399



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Find two consecutive odd numbers whose product is 399? - Answers

https://math.answers.com/algebra/Find_two_consecutive_odd_numbers_whose_product_is_399

If one of the numbers is x, then the other number is x + 2. So, x(x + 2) = 399 x^2 + 2x = 399 Complete the square by adding 1 at both sides ; x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2 (x + 1)^2 = 400 x + 1 = (+ & - )(square root of 400) subtract 1 to both sides x = -1 (+ & -) 20 x = -1 + 20 or x = -1 - 20 x = 19 or x = -21 So, x + 2 = 19 + 2 = 21 or x + 2 = - 21 + 2 = - 19 Thus the numbers are: 19 and 21 or -19 and - 21 Check: (19)(21) = 399 (-19)(-21) = 399



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https://math.answers.com/algebra/Find_two_consecutive_odd_numbers_whose_product_is_399

Find two consecutive odd numbers whose product is 399? - Answers

If one of the numbers is x, then the other number is x + 2. So, x(x + 2) = 399 x^2 + 2x = 399 Complete the square by adding 1 at both sides ; x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2 (x + 1)^2 = 400 x + 1 = (+ & - )(square root of 400) subtract 1 to both sides x = -1 (+ & -) 20 x = -1 + 20 or x = -1 - 20 x = 19 or x = -21 So, x + 2 = 19 + 2 = 21 or x + 2 = - 21 + 2 = - 19 Thus the numbers are: 19 and 21 or -19 and - 21 Check: (19)(21) = 399 (-19)(-21) = 399

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      If one of the numbers is x, then the other number is x + 2. So, x(x + 2) = 399 x^2 + 2x = 399 Complete the square by adding 1 at both sides ; x^2 + 2x + 1 = 399 + 1 Use the formula: (a + b)^2 = a^2 + 2ab + b^2 (x + 1)^2 = 400 x + 1 = (+ & - )(square root of 400) subtract 1 to both sides x = -1 (+ & -) 20 x = -1 + 20 or x = -1 - 20 x = 19 or x = -21 So, x + 2 = 19 + 2 = 21 or x + 2 = - 21 + 2 = - 19 Thus the numbers are: 19 and 21 or -19 and - 21 Check: (19)(21) = 399 (-19)(-21) = 399
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