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https://math.answers.com/algebra/How_many_3_letter_combinations_with_26_letters_without_repetition

How many 3 letter combinations with 26 letters without repetition? - Answers

I assume you mean no repetition to be ABC and not ABA OR AAB. That being said this is very straight forward. The first position can potentially have any of the 26 letters. the second position can only have 1 of 25 possible letters because one letter has already be selected for the first position. And the final position can only have 1 of 24 possible letters because two letters have already been selected for the first two positions. Just multiply the number of possibilities for each position together and you have your answer. 26 * 25 * 24 = 15600 possible combinations.



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How many 3 letter combinations with 26 letters without repetition? - Answers

https://math.answers.com/algebra/How_many_3_letter_combinations_with_26_letters_without_repetition

I assume you mean no repetition to be ABC and not ABA OR AAB. That being said this is very straight forward. The first position can potentially have any of the 26 letters. the second position can only have 1 of 25 possible letters because one letter has already be selected for the first position. And the final position can only have 1 of 24 possible letters because two letters have already been selected for the first two positions. Just multiply the number of possibilities for each position together and you have your answer. 26 * 25 * 24 = 15600 possible combinations.



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https://math.answers.com/algebra/How_many_3_letter_combinations_with_26_letters_without_repetition

How many 3 letter combinations with 26 letters without repetition? - Answers

I assume you mean no repetition to be ABC and not ABA OR AAB. That being said this is very straight forward. The first position can potentially have any of the 26 letters. the second position can only have 1 of 25 possible letters because one letter has already be selected for the first position. And the final position can only have 1 of 24 possible letters because two letters have already been selected for the first two positions. Just multiply the number of possibilities for each position together and you have your answer. 26 * 25 * 24 = 15600 possible combinations.

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      I assume you mean no repetition to be ABC and not ABA OR AAB. That being said this is very straight forward. The first position can potentially have any of the 26 letters. the second position can only have 1 of 25 possible letters because one letter has already be selected for the first position. And the final position can only have 1 of 24 possible letters because two letters have already been selected for the first two positions. Just multiply the number of possibilities for each position together and you have your answer. 26 * 25 * 24 = 15600 possible combinations.

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