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What are 3 consecutive integers that equal 114? - Answers

Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.



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What are 3 consecutive integers that equal 114? - Answers

https://math.answers.com/algebra/What_are_3_consecutive_integers_that_equal_114

Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.



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https://math.answers.com/algebra/What_are_3_consecutive_integers_that_equal_114

What are 3 consecutive integers that equal 114? - Answers

Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.

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      Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.

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