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The sum of the first 500 even numbers? - Answers

From arithmetic series formula the sum of n terms is Sn= (n/2)(a + tn) where n is the number of terms to be added, a is the first term and tn is the last term. We want to add 500 terms so n = 500. The first even integer is 2 so a=2. The 500th even integer is 1000 so t500 = 1000. S500 = (500/2)(2 + 1000) = 250500



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The sum of the first 500 even numbers? - Answers

https://math.answers.com/basic-math/The_sum_of_the_first_500_even_numbers

From arithmetic series formula the sum of n terms is Sn= (n/2)(a + tn) where n is the number of terms to be added, a is the first term and tn is the last term. We want to add 500 terms so n = 500. The first even integer is 2 so a=2. The 500th even integer is 1000 so t500 = 1000. S500 = (500/2)(2 + 1000) = 250500



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https://math.answers.com/basic-math/The_sum_of_the_first_500_even_numbers

The sum of the first 500 even numbers? - Answers

From arithmetic series formula the sum of n terms is Sn= (n/2)(a + tn) where n is the number of terms to be added, a is the first term and tn is the last term. We want to add 500 terms so n = 500. The first even integer is 2 so a=2. The 500th even integer is 1000 so t500 = 1000. S500 = (500/2)(2 + 1000) = 250500

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      From arithmetic series formula the sum of n terms is Sn= (n/2)(a + tn) where n is the number of terms to be added, a is the first term and tn is the last term. We want to add 500 terms so n = 500. The first even integer is 2 so a=2. The 500th even integer is 1000 so t500 = 1000. S500 = (500/2)(2 + 1000) = 250500
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