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What are the 20 factors of 2000? - Answers
To find the factors of a number, start with its prime factors. In the case of 2000, these are 2 x 2 x 2 x 2 x 5 x 5 x 5. Multiplying different combinations of these gives us the whole list of factors: 1 22 x 2 = 42 x 2 x 2 = 82 x 2 x 2 x 2 = 1655 x 5 = 255 x 5 x 5 = 1252 x 5 =102 x 5 x 5 = 502 x 5 x 5 = 2502 x 2 x 5 = 202 x 2 x 5 x 5 = 1002 x 2 x 5 x 5 x 5 = 5002 x 2 x 2 x 5 = 402 x 2 x 2 x 5 x 5 = 2002 x 2 x 2 x 5 x 5 x 5 = 10002 x 2 x 2 x 2 x 5 = 802 x 2 x 2 x 2 x 5 x 5 = 400[2 x 2 x 2 x 2 x 5 x 5 x 5 = 2000] So you're quite right, 2000 does have 20 factors.
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What are the 20 factors of 2000? - Answers
To find the factors of a number, start with its prime factors. In the case of 2000, these are 2 x 2 x 2 x 2 x 5 x 5 x 5. Multiplying different combinations of these gives us the whole list of factors: 1 22 x 2 = 42 x 2 x 2 = 82 x 2 x 2 x 2 = 1655 x 5 = 255 x 5 x 5 = 1252 x 5 =102 x 5 x 5 = 502 x 5 x 5 = 2502 x 2 x 5 = 202 x 2 x 5 x 5 = 1002 x 2 x 5 x 5 x 5 = 5002 x 2 x 2 x 5 = 402 x 2 x 2 x 5 x 5 = 2002 x 2 x 2 x 5 x 5 x 5 = 10002 x 2 x 2 x 2 x 5 = 802 x 2 x 2 x 2 x 5 x 5 = 400[2 x 2 x 2 x 2 x 5 x 5 x 5 = 2000] So you're quite right, 2000 does have 20 factors.
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What are the 20 factors of 2000? - Answers
To find the factors of a number, start with its prime factors. In the case of 2000, these are 2 x 2 x 2 x 2 x 5 x 5 x 5. Multiplying different combinations of these gives us the whole list of factors: 1 22 x 2 = 42 x 2 x 2 = 82 x 2 x 2 x 2 = 1655 x 5 = 255 x 5 x 5 = 1252 x 5 =102 x 5 x 5 = 502 x 5 x 5 = 2502 x 2 x 5 = 202 x 2 x 5 x 5 = 1002 x 2 x 5 x 5 x 5 = 5002 x 2 x 2 x 5 = 402 x 2 x 2 x 5 x 5 = 2002 x 2 x 2 x 5 x 5 x 5 = 10002 x 2 x 2 x 2 x 5 = 802 x 2 x 2 x 2 x 5 x 5 = 400[2 x 2 x 2 x 2 x 5 x 5 x 5 = 2000] So you're quite right, 2000 does have 20 factors.
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