math.answers.com/geometry/How_do_you_rotate_a_figure_90_degrees_clockwise_about_origin

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/geometry/How_do_you_rotate_a_figure_90_degrees_clockwise_about_origin

How do you rotate a figure 90 degrees clockwise about origin? - Answers

Switch the coordinates and change the sign of the second one by multiplying it by negative 1. Here are some examples and a more general way to understand the problem. Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant. The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4) We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). . In the case of p=(1,0) the new point is p'= (0, -1) One can use a matrix where the first row is cos(a), sin(a) and the second row is -sin(a) cos(a) for any clockwise rotation of a degrees about the origin. If we let a=90 degrees we have [0 1] as the first row and [-1 0] as the second row. So the matrix is: |0 1| |-1 0| Call that matrix M So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point. If p=(-4,2) then Mp is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4 So p'=(2,4) Try it with (1,0) x'=1*0+0*1=0 y'=-1*1+0*1=-1 so p'=(0,-1) and (1,0)->(0,-1) How about the point on the y axis (0,1), it should go to the point (1,0) 0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)



Bing

How do you rotate a figure 90 degrees clockwise about origin? - Answers

https://math.answers.com/geometry/How_do_you_rotate_a_figure_90_degrees_clockwise_about_origin

Switch the coordinates and change the sign of the second one by multiplying it by negative 1. Here are some examples and a more general way to understand the problem. Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant. The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4) We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). . In the case of p=(1,0) the new point is p'= (0, -1) One can use a matrix where the first row is cos(a), sin(a) and the second row is -sin(a) cos(a) for any clockwise rotation of a degrees about the origin. If we let a=90 degrees we have [0 1] as the first row and [-1 0] as the second row. So the matrix is: |0 1| |-1 0| Call that matrix M So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point. If p=(-4,2) then Mp is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4 So p'=(2,4) Try it with (1,0) x'=1*0+0*1=0 y'=-1*1+0*1=-1 so p'=(0,-1) and (1,0)->(0,-1) How about the point on the y axis (0,1), it should go to the point (1,0) 0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)



DuckDuckGo

https://math.answers.com/geometry/How_do_you_rotate_a_figure_90_degrees_clockwise_about_origin

How do you rotate a figure 90 degrees clockwise about origin? - Answers

Switch the coordinates and change the sign of the second one by multiplying it by negative 1. Here are some examples and a more general way to understand the problem. Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant. The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4) We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). . In the case of p=(1,0) the new point is p'= (0, -1) One can use a matrix where the first row is cos(a), sin(a) and the second row is -sin(a) cos(a) for any clockwise rotation of a degrees about the origin. If we let a=90 degrees we have [0 1] as the first row and [-1 0] as the second row. So the matrix is: |0 1| |-1 0| Call that matrix M So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point. If p=(-4,2) then Mp is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4 So p'=(2,4) Try it with (1,0) x'=1*0+0*1=0 y'=-1*1+0*1=-1 so p'=(0,-1) and (1,0)->(0,-1) How about the point on the y axis (0,1), it should go to the point (1,0) 0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)

  • General Meta Tags

    22
    • title
      How do you rotate a figure 90 degrees clockwise about origin? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1
  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      Switch the coordinates and change the sign of the second one by multiplying it by negative 1. Here are some examples and a more general way to understand the problem. Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant. The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4) We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). . In the case of p=(1,0) the new point is p'= (0, -1) One can use a matrix where the first row is cos(a), sin(a) and the second row is -sin(a) cos(a) for any clockwise rotation of a degrees about the origin. If we let a=90 degrees we have [0 1] as the first row and [-1 0] as the second row. So the matrix is: |0 1| |-1 0| Call that matrix M So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point. If p=(-4,2) then Mp is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4 So p'=(2,4) Try it with (1,0) x'=1*0+0*1=0 y'=-1*1+0*1=-1 so p'=(0,-1) and (1,0)->(0,-1) How about the point on the y axis (0,1), it should go to the point (1,0) 0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)
  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image
  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/geometry/How_do_you_rotate_a_figure_90_degrees_clockwise_about_origin
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58