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How do you calculate area of a scalene triangle? - Answers

Suppose the sides are of length x, y and z units. Let s = (x + y + z)/2 Then Area = sqrt[s*(s - x)*(s - y)*(s - z)] square units. Alternatively, the angle between the lines with lengths y and z is arccos[(y^2 + z^2 - x^2)/(2*y*z)] = theta, say. And then area = 0.5*y*z*sin(theta).



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How do you calculate area of a scalene triangle? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_calculate_area_of_a_scalene_triangle

Suppose the sides are of length x, y and z units. Let s = (x + y + z)/2 Then Area = sqrt[s*(s - x)*(s - y)*(s - z)] square units. Alternatively, the angle between the lines with lengths y and z is arccos[(y^2 + z^2 - x^2)/(2*y*z)] = theta, say. And then area = 0.5*y*z*sin(theta).



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https://math.answers.com/math-and-arithmetic/How_do_you_calculate_area_of_a_scalene_triangle

How do you calculate area of a scalene triangle? - Answers

Suppose the sides are of length x, y and z units. Let s = (x + y + z)/2 Then Area = sqrt[s*(s - x)*(s - y)*(s - z)] square units. Alternatively, the angle between the lines with lengths y and z is arccos[(y^2 + z^2 - x^2)/(2*y*z)] = theta, say. And then area = 0.5*y*z*sin(theta).

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      Suppose the sides are of length x, y and z units. Let s = (x + y + z)/2 Then Area = sqrt[s*(s - x)*(s - y)*(s - z)] square units. Alternatively, the angle between the lines with lengths y and z is arccos[(y^2 + z^2 - x^2)/(2*y*z)] = theta, say. And then area = 0.5*y*z*sin(theta).

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