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How do you convert -2(x 1)(x-3) to general form? - Answers

To convert (-2(x + 1)(x - 3)) to general form, first expand the expression by using the distributive property. Multiply (-2) by each term in the binomials: [ -2[(x)(x) + (x)(-3) + (1)(x) + (1)(-3)] = -2[x^2 - 3x + x - 3] ] This simplifies to: [ -2[x^2 - 2x - 3] = -2x^2 + 4x + 6 ] Thus, the general form is (-2x^2 + 4x + 6).



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How do you convert -2(x 1)(x-3) to general form? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_convert_-2(x_1)(x-3)_to_general_form

To convert (-2(x + 1)(x - 3)) to general form, first expand the expression by using the distributive property. Multiply (-2) by each term in the binomials: [ -2[(x)(x) + (x)(-3) + (1)(x) + (1)(-3)] = -2[x^2 - 3x + x - 3] ] This simplifies to: [ -2[x^2 - 2x - 3] = -2x^2 + 4x + 6 ] Thus, the general form is (-2x^2 + 4x + 6).



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https://math.answers.com/math-and-arithmetic/How_do_you_convert_-2(x_1)(x-3)_to_general_form

How do you convert -2(x 1)(x-3) to general form? - Answers

To convert (-2(x + 1)(x - 3)) to general form, first expand the expression by using the distributive property. Multiply (-2) by each term in the binomials: [ -2[(x)(x) + (x)(-3) + (1)(x) + (1)(-3)] = -2[x^2 - 3x + x - 3] ] This simplifies to: [ -2[x^2 - 2x - 3] = -2x^2 + 4x + 6 ] Thus, the general form is (-2x^2 + 4x + 6).

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      To convert (-2(x + 1)(x - 3)) to general form, first expand the expression by using the distributive property. Multiply (-2) by each term in the binomials: [ -2[(x)(x) + (x)(-3) + (1)(x) + (1)(-3)] = -2[x^2 - 3x + x - 3] ] This simplifies to: [ -2[x^2 - 2x - 3] = -2x^2 + 4x + 6 ] Thus, the general form is (-2x^2 + 4x + 6).

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