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How do you divide 518 by 7? - Answers
7)518 = We say 7 into 51 goes 7 times remainder '2' ( 7 x 7 = 49 + 2 = 51) So the first part of the answer is '7' Hence 7)518 = 7 ... The remainder '2' is combined weith the '8' as;28; ( NOT 10). We say 7 into 28 goes 4 times remainder '0' ( 7 x 4 = 28 + 0 = 28) So thesecond part of ther answer is ' 4'. Hence 7)518 = 74 The answer/ NB Once the remainder is reduced to 'zero' that is the dend of the division.
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How do you divide 518 by 7? - Answers
7)518 = We say 7 into 51 goes 7 times remainder '2' ( 7 x 7 = 49 + 2 = 51) So the first part of the answer is '7' Hence 7)518 = 7 ... The remainder '2' is combined weith the '8' as;28; ( NOT 10). We say 7 into 28 goes 4 times remainder '0' ( 7 x 4 = 28 + 0 = 28) So thesecond part of ther answer is ' 4'. Hence 7)518 = 74 The answer/ NB Once the remainder is reduced to 'zero' that is the dend of the division.
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How do you divide 518 by 7? - Answers
7)518 = We say 7 into 51 goes 7 times remainder '2' ( 7 x 7 = 49 + 2 = 51) So the first part of the answer is '7' Hence 7)518 = 7 ... The remainder '2' is combined weith the '8' as;28; ( NOT 10). We say 7 into 28 goes 4 times remainder '0' ( 7 x 4 = 28 + 0 = 28) So thesecond part of ther answer is ' 4'. Hence 7)518 = 74 The answer/ NB Once the remainder is reduced to 'zero' that is the dend of the division.
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- og:description7)518 = We say 7 into 51 goes 7 times remainder '2' ( 7 x 7 = 49 + 2 = 51) So the first part of the answer is '7' Hence 7)518 = 7 ... The remainder '2' is combined weith the '8' as;28; ( NOT 10). We say 7 into 28 goes 4 times remainder '0' ( 7 x 4 = 28 + 0 = 28) So thesecond part of ther answer is ' 4'. Hence 7)518 = 74 The answer/ NB Once the remainder is reduced to 'zero' that is the dend of the division.
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