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How do you graph y equals 6x plus 5? - Answers

You need to know the domain over which you are required to graph the function. Suppose it is between 0 and 10. Choose x = 0 and substitute this value into the equation y = 6x + 5. It becomes y = 6*0 + 5 = 0 + 5 = 5. So mark the point (0, 5) on the grid. Choose x = 10 and substitute this value into the equation y = 6x + 5. It becomesy = 6*10 + 5 = 60 + 5 = 65. So mark the point (10, 65) on the grid. You can join these two points with a straight line and you are done. However, it is safer to do a third point, say x = 5.The equation then gives y = 6*5 + 5 = 30 + 5 and so mark the point (5, 35). If the 3 points are in the same straight line (they are collinear) you are home. If not, you have made a mistake in one of your calculations.



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How do you graph y equals 6x plus 5? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_graph_y_equals_6x_plus_5

You need to know the domain over which you are required to graph the function. Suppose it is between 0 and 10. Choose x = 0 and substitute this value into the equation y = 6x + 5. It becomes y = 6*0 + 5 = 0 + 5 = 5. So mark the point (0, 5) on the grid. Choose x = 10 and substitute this value into the equation y = 6x + 5. It becomesy = 6*10 + 5 = 60 + 5 = 65. So mark the point (10, 65) on the grid. You can join these two points with a straight line and you are done. However, it is safer to do a third point, say x = 5.The equation then gives y = 6*5 + 5 = 30 + 5 and so mark the point (5, 35). If the 3 points are in the same straight line (they are collinear) you are home. If not, you have made a mistake in one of your calculations.



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https://math.answers.com/math-and-arithmetic/How_do_you_graph_y_equals_6x_plus_5

How do you graph y equals 6x plus 5? - Answers

You need to know the domain over which you are required to graph the function. Suppose it is between 0 and 10. Choose x = 0 and substitute this value into the equation y = 6x + 5. It becomes y = 6*0 + 5 = 0 + 5 = 5. So mark the point (0, 5) on the grid. Choose x = 10 and substitute this value into the equation y = 6x + 5. It becomesy = 6*10 + 5 = 60 + 5 = 65. So mark the point (10, 65) on the grid. You can join these two points with a straight line and you are done. However, it is safer to do a third point, say x = 5.The equation then gives y = 6*5 + 5 = 30 + 5 and so mark the point (5, 35). If the 3 points are in the same straight line (they are collinear) you are home. If not, you have made a mistake in one of your calculations.

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      You need to know the domain over which you are required to graph the function. Suppose it is between 0 and 10. Choose x = 0 and substitute this value into the equation y = 6x + 5. It becomes y = 6*0 + 5 = 0 + 5 = 5. So mark the point (0, 5) on the grid. Choose x = 10 and substitute this value into the equation y = 6x + 5. It becomesy = 6*10 + 5 = 60 + 5 = 65. So mark the point (10, 65) on the grid. You can join these two points with a straight line and you are done. However, it is safer to do a third point, say x = 5.The equation then gives y = 6*5 + 5 = 30 + 5 and so mark the point (5, 35). If the 3 points are in the same straight line (they are collinear) you are home. If not, you have made a mistake in one of your calculations.
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