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https://math.answers.com/math-and-arithmetic/How_do_you_illustrate_the_linear_line_in_a_regression_analysis

How do you illustrate the linear line in a regression analysis? - Answers

Age of Employee (X)% (y)(x*y)(x*x)(20 - 30) 201020 * 10 = 20020 * 20 = 400(30 - 40) 157.515 * 7.5 = 112.515 * 15 = 225(40 - 50) 10510 * 5 = 5010 * 10 = 100(50 - 60) 31.53 * 1.5 = 4.53 * 3 = 9(60 - 65) 212 * 1 = 22 * 2 = 4Σx = 50Σy = 25Σxy = 369Σx2 = 738(b) = (NΣXY - (ΣX)(ΣY)) / (NΣX2 - (ΣX)2)(b) = ((5)*(75)-(50)*(25))/((5)*(369)-(50)2)(b)= (375 - 1250) / (1845 - 2500)(b) = 875/655(b) = 1.4(a) = (ΣY - b(ΣX)) / N(a) = (25-1.4(50))/5(a) = (25 - 40.5)/5(a) = -3.1



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How do you illustrate the linear line in a regression analysis? - Answers

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Age of Employee (X)% (y)(x*y)(x*x)(20 - 30) 201020 * 10 = 20020 * 20 = 400(30 - 40) 157.515 * 7.5 = 112.515 * 15 = 225(40 - 50) 10510 * 5 = 5010 * 10 = 100(50 - 60) 31.53 * 1.5 = 4.53 * 3 = 9(60 - 65) 212 * 1 = 22 * 2 = 4Σx = 50Σy = 25Σxy = 369Σx2 = 738(b) = (NΣXY - (ΣX)(ΣY)) / (NΣX2 - (ΣX)2)(b) = ((5)*(75)-(50)*(25))/((5)*(369)-(50)2)(b)= (375 - 1250) / (1845 - 2500)(b) = 875/655(b) = 1.4(a) = (ΣY - b(ΣX)) / N(a) = (25-1.4(50))/5(a) = (25 - 40.5)/5(a) = -3.1



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https://math.answers.com/math-and-arithmetic/How_do_you_illustrate_the_linear_line_in_a_regression_analysis

How do you illustrate the linear line in a regression analysis? - Answers

Age of Employee (X)% (y)(x*y)(x*x)(20 - 30) 201020 * 10 = 20020 * 20 = 400(30 - 40) 157.515 * 7.5 = 112.515 * 15 = 225(40 - 50) 10510 * 5 = 5010 * 10 = 100(50 - 60) 31.53 * 1.5 = 4.53 * 3 = 9(60 - 65) 212 * 1 = 22 * 2 = 4Σx = 50Σy = 25Σxy = 369Σx2 = 738(b) = (NΣXY - (ΣX)(ΣY)) / (NΣX2 - (ΣX)2)(b) = ((5)*(75)-(50)*(25))/((5)*(369)-(50)2)(b)= (375 - 1250) / (1845 - 2500)(b) = 875/655(b) = 1.4(a) = (ΣY - b(ΣX)) / N(a) = (25-1.4(50))/5(a) = (25 - 40.5)/5(a) = -3.1

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      Age of Employee (X)% (y)(x*y)(x*x)(20 - 30) 201020 * 10 = 20020 * 20 = 400(30 - 40) 157.515 * 7.5 = 112.515 * 15 = 225(40 - 50) 10510 * 5 = 5010 * 10 = 100(50 - 60) 31.53 * 1.5 = 4.53 * 3 = 9(60 - 65) 212 * 1 = 22 * 2 = 4Σx = 50Σy = 25Σxy = 369Σx2 = 738(b) = (NΣXY - (ΣX)(ΣY)) / (NΣX2 - (ΣX)2)(b) = ((5)*(75)-(50)*(25))/((5)*(369)-(50)2)(b)= (375 - 1250) / (1845 - 2500)(b) = 875/655(b) = 1.4(a) = (ΣY - b(ΣX)) / N(a) = (25-1.4(50))/5(a) = (25 - 40.5)/5(a) = -3.1

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