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How do you solve 2x squared minus 5x plus 1 equals 0? - Answers

2.282x2 - 5x + 1 = 0by Quadratic Formula: x = (-b+√b2-4ac)/2aa = 2b = -5c = 1x = [-(-5) +√(-5)2 - 4(2)(1)]/2 (2)= (5 + √25 - 8)/4= (5 + √17)/4= (5 +4.12)/4= 2.28



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How do you solve 2x squared minus 5x plus 1 equals 0? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_2x_squared_minus_5x_plus_1_equals_0

2.282x2 - 5x + 1 = 0by Quadratic Formula: x = (-b+√b2-4ac)/2aa = 2b = -5c = 1x = [-(-5) +√(-5)2 - 4(2)(1)]/2 (2)= (5 + √25 - 8)/4= (5 + √17)/4= (5 +4.12)/4= 2.28



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_2x_squared_minus_5x_plus_1_equals_0

How do you solve 2x squared minus 5x plus 1 equals 0? - Answers

2.282x2 - 5x + 1 = 0by Quadratic Formula: x = (-b+√b2-4ac)/2aa = 2b = -5c = 1x = [-(-5) +√(-5)2 - 4(2)(1)]/2 (2)= (5 + √25 - 8)/4= (5 + √17)/4= (5 +4.12)/4= 2.28

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      2.282x2 - 5x + 1 = 0by Quadratic Formula: x = (-b+√b2-4ac)/2aa = 2b = -5c = 1x = [-(-5) +√(-5)2 - 4(2)(1)]/2 (2)= (5 + √25 - 8)/4= (5 + √17)/4= (5 +4.12)/4= 2.28

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