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How do you solve 3x2 equals -9 by quadratic formula? - Answers

If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers. For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0 Then a = 3, b = 0 and c = 9 So x = [0 ± √(02 - 4*3*9)]/(2*3) = √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.



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How do you solve 3x2 equals -9 by quadratic formula? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_3x2_equals_-9_by_quadratic_formula

If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers. For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0 Then a = 3, b = 0 and c = 9 So x = [0 ± √(02 - 4*3*9)]/(2*3) = √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_3x2_equals_-9_by_quadratic_formula

How do you solve 3x2 equals -9 by quadratic formula? - Answers

If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers. For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0 Then a = 3, b = 0 and c = 9 So x = [0 ± √(02 - 4*3*9)]/(2*3) = √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.

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      If you are at a level that you need to ask this question then the likelihood is that you have made a mistake, since you are not likely to have learned about imaginary (or complex) numbers. For the quadratic formula, first rewrite the equation as: 3x2 + 0x + 9 = 0 Then a = 3, b = 0 and c = 9 So x = [0 ± √(02 - 4*3*9)]/(2*3) = √-108/6 = √-3 = i√3 where i is the imaginary square root of -1.

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