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How do you solve abacus 6 challenge master 8? - Answers
Abacus 6 challenge master 8 looks at consecutive addition.(After my husband and 10 year old daughter struggled with this all day - I thought the following might be useful to other parents also struggling. It is not definitive (I am not a Maths graduate), but it works.)A very useful table can be produced (Jackson's Table) - preferably with the help of Excel or similar. The first few lines are produced below.No. 2 3 4 5 6 (consecutive numbers)1 3 6 10 15 212 5 9 14 20 273 7 12 18 25 33..n 2n+1 3n 4n+6 5n+10 6n+15The numbers set in the problem can all then be found; hence 9 appears twice and 75 appears 4 times.The observations to be drawn are that:all odd numbers can be made from 2 consecutive numbers, but that even numbers cannot.Any number divisible by 3 (except 3 itself) can be made by adding 3 consecutive numbersAny 5 consecutive numbers added together will always give a multiple of 5Multiples of 4 cannot be made by adding consecutive numbers unless that multiple is also a multiple of 3 or 5
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How do you solve abacus 6 challenge master 8? - Answers
Abacus 6 challenge master 8 looks at consecutive addition.(After my husband and 10 year old daughter struggled with this all day - I thought the following might be useful to other parents also struggling. It is not definitive (I am not a Maths graduate), but it works.)A very useful table can be produced (Jackson's Table) - preferably with the help of Excel or similar. The first few lines are produced below.No. 2 3 4 5 6 (consecutive numbers)1 3 6 10 15 212 5 9 14 20 273 7 12 18 25 33..n 2n+1 3n 4n+6 5n+10 6n+15The numbers set in the problem can all then be found; hence 9 appears twice and 75 appears 4 times.The observations to be drawn are that:all odd numbers can be made from 2 consecutive numbers, but that even numbers cannot.Any number divisible by 3 (except 3 itself) can be made by adding 3 consecutive numbersAny 5 consecutive numbers added together will always give a multiple of 5Multiples of 4 cannot be made by adding consecutive numbers unless that multiple is also a multiple of 3 or 5
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How do you solve abacus 6 challenge master 8? - Answers
Abacus 6 challenge master 8 looks at consecutive addition.(After my husband and 10 year old daughter struggled with this all day - I thought the following might be useful to other parents also struggling. It is not definitive (I am not a Maths graduate), but it works.)A very useful table can be produced (Jackson's Table) - preferably with the help of Excel or similar. The first few lines are produced below.No. 2 3 4 5 6 (consecutive numbers)1 3 6 10 15 212 5 9 14 20 273 7 12 18 25 33..n 2n+1 3n 4n+6 5n+10 6n+15The numbers set in the problem can all then be found; hence 9 appears twice and 75 appears 4 times.The observations to be drawn are that:all odd numbers can be made from 2 consecutive numbers, but that even numbers cannot.Any number divisible by 3 (except 3 itself) can be made by adding 3 consecutive numbersAny 5 consecutive numbers added together will always give a multiple of 5Multiples of 4 cannot be made by adding consecutive numbers unless that multiple is also a multiple of 3 or 5
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