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How do you solve an equation with brackets side by side? - Answers
Do you mean like: (ax +b)(cx+d) = 0 For the LHS (Left Hand Side) to be zero, either (or both) of the brackets must be zero, that is: ax+b = 0 or cx+d = 0 which can be solved quite simply by rearranging them: ax+b=0 -> x = -b/a cx+d=0 -> x = -d/c So the solution would be x = -b/a or x = -d/c. If this is not what you mean, ask again giving an example. Perhaps, despite being correct, you may be over thinking this. The contributor may mean simply what is meant by two sets of brackets next to each other. In which case the answer is: The results of the pair of brackets are multiplied together.
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How do you solve an equation with brackets side by side? - Answers
Do you mean like: (ax +b)(cx+d) = 0 For the LHS (Left Hand Side) to be zero, either (or both) of the brackets must be zero, that is: ax+b = 0 or cx+d = 0 which can be solved quite simply by rearranging them: ax+b=0 -> x = -b/a cx+d=0 -> x = -d/c So the solution would be x = -b/a or x = -d/c. If this is not what you mean, ask again giving an example. Perhaps, despite being correct, you may be over thinking this. The contributor may mean simply what is meant by two sets of brackets next to each other. In which case the answer is: The results of the pair of brackets are multiplied together.
DuckDuckGo
How do you solve an equation with brackets side by side? - Answers
Do you mean like: (ax +b)(cx+d) = 0 For the LHS (Left Hand Side) to be zero, either (or both) of the brackets must be zero, that is: ax+b = 0 or cx+d = 0 which can be solved quite simply by rearranging them: ax+b=0 -> x = -b/a cx+d=0 -> x = -d/c So the solution would be x = -b/a or x = -d/c. If this is not what you mean, ask again giving an example. Perhaps, despite being correct, you may be over thinking this. The contributor may mean simply what is meant by two sets of brackets next to each other. In which case the answer is: The results of the pair of brackets are multiplied together.
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