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How do you solve for x in (2y 1)(y 14)0? - Answers

To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).



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How do you solve for x in (2y 1)(y 14)0? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_for_x_in_(2y_1)(y_14)0

To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_for_x_in_(2y_1)(y_14)0

How do you solve for x in (2y 1)(y 14)0? - Answers

To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).

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      To solve for ( x ) in the equation ((2y + 1)(y - 14) = 0), you can use the zero product property, which states that if the product of two factors is zero, at least one of the factors must be zero. Set each factor to zero: ( 2y + 1 = 0 ) and ( y - 14 = 0 ). Solving these gives ( y = -\frac{1}{2} ) and ( y = 14 ). Thus, the solutions for ( y ) are ( y = -\frac{1}{2} ) and ( y = 14 ).

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