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How do you solve this 129x-6? - Answers

Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.



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How do you solve this 129x-6? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_this_129x-6

Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_this_129x-6

How do you solve this 129x-6? - Answers

Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.

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      Equations can be solved, but you have not given us an equation, just a term. The most typical form for an algebraic equation would be to start with zero, so perhaps you intended to say, 129x - 6 = 0 which would then be easy to solve. Add 6 to both sides, 129x = 6 then divide both sides by 129, x = 6/129 which we can simplify to 2/43. This expression can be represented as a linear equation in two variables. Let's impose another variable, say y. Then we have y = 129x - 6 which has infinitely many solutions of the form (x, y). Pick a value for x and input it into the equation to obtain a corresponding value for y. There are two special solutions, (2/43, 0) and (0, -6), which lies on the x- and y-axis.
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