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How do you solve x2 -3x -20? - Answers

You try to find factors of 20 that add to 3. Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula: x = (-b +/- (sqrt(b squared - 4 ac)))/2a In your equation a = 1, b = -3 and c = -20 (3 +/- (sqrt(9 + 80)))/2 = (3 +/- sqrt 89)/2 = (3 +/- 9.434)/2 = 12.434/2 and -6.434/2 = 6.217 and -3.217 which are the values for x when your equation equals zero.



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How do you solve x2 -3x -20? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x2_-3x_-20

You try to find factors of 20 that add to 3. Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula: x = (-b +/- (sqrt(b squared - 4 ac)))/2a In your equation a = 1, b = -3 and c = -20 (3 +/- (sqrt(9 + 80)))/2 = (3 +/- sqrt 89)/2 = (3 +/- 9.434)/2 = 12.434/2 and -6.434/2 = 6.217 and -3.217 which are the values for x when your equation equals zero.



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_x2_-3x_-20

How do you solve x2 -3x -20? - Answers

You try to find factors of 20 that add to 3. Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula: x = (-b +/- (sqrt(b squared - 4 ac)))/2a In your equation a = 1, b = -3 and c = -20 (3 +/- (sqrt(9 + 80)))/2 = (3 +/- sqrt 89)/2 = (3 +/- 9.434)/2 = 12.434/2 and -6.434/2 = 6.217 and -3.217 which are the values for x when your equation equals zero.

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      You try to find factors of 20 that add to 3. Factors of 20 are 1/20, 2/10 & 4/5. You can't make 3 out of any of these so you have to use the quadratic formula: x = (-b +/- (sqrt(b squared - 4 ac)))/2a In your equation a = 1, b = -3 and c = -20 (3 +/- (sqrt(9 + 80)))/2 = (3 +/- sqrt 89)/2 = (3 +/- 9.434)/2 = 12.434/2 and -6.434/2 = 6.217 and -3.217 which are the values for x when your equation equals zero.

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