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How does knowing that 5x4 equals 20 help you find 5x8? - Answers

8 = 4*2 So 5*8 = 5*(4*2) which, by the associative property, = (5*4)*2 = 20*2 Can you do 20*2 more easily than 5*8? If not, you need another round of associate property. 20 = 10*2 So 20*2 = (10*2)*2 = 10*(2*2) = 10*4 And if you cannot do 10*4 then this question is beyond you anyway and knowing 5*4 is not going to help.



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How does knowing that 5x4 equals 20 help you find 5x8? - Answers

https://math.answers.com/math-and-arithmetic/How_does_knowing_that_5x4_equals_20_help_you_find_5x8

8 = 4*2 So 5*8 = 5*(4*2) which, by the associative property, = (5*4)*2 = 20*2 Can you do 20*2 more easily than 5*8? If not, you need another round of associate property. 20 = 10*2 So 20*2 = (10*2)*2 = 10*(2*2) = 10*4 And if you cannot do 10*4 then this question is beyond you anyway and knowing 5*4 is not going to help.



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https://math.answers.com/math-and-arithmetic/How_does_knowing_that_5x4_equals_20_help_you_find_5x8

How does knowing that 5x4 equals 20 help you find 5x8? - Answers

8 = 4*2 So 5*8 = 5*(4*2) which, by the associative property, = (5*4)*2 = 20*2 Can you do 20*2 more easily than 5*8? If not, you need another round of associate property. 20 = 10*2 So 20*2 = (10*2)*2 = 10*(2*2) = 10*4 And if you cannot do 10*4 then this question is beyond you anyway and knowing 5*4 is not going to help.

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      8 = 4*2 So 5*8 = 5*(4*2) which, by the associative property, = (5*4)*2 = 20*2 Can you do 20*2 more easily than 5*8? If not, you need another round of associate property. 20 = 10*2 So 20*2 = (10*2)*2 = 10*(2*2) = 10*4 And if you cannot do 10*4 then this question is beyond you anyway and knowing 5*4 is not going to help.

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