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How is math used with the pythagorean theorem? - Answers

It is used to measure the area of c2 which will be the diagonal slope for ANY triangle. The equation will always be a2 + b2 = c2 (2)= squared a(2) and b(2) will be either side of a right angle of a triangle. C(2) is the long diagonal slope that joins the end of a(2) and c(2) to make a triangle. for example: If a(2) is 4cm long and b(2) is 5cm long this will be the equation to solve the area of c(2) a(2) + b(2) = c(2) 4(2) + 5(2) = c(2) 16 + 25 = c(2) 41 = c(2) You get 41 by adding 16 & 25 and then you find the square root of 41 6.40312 = C√ So the area of c(2) is 6.40312cm Hope this helps :)



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How is math used with the pythagorean theorem? - Answers

https://math.answers.com/math-and-arithmetic/How_is_math_used_with_the_pythagorean_theorem

It is used to measure the area of c2 which will be the diagonal slope for ANY triangle. The equation will always be a2 + b2 = c2 (2)= squared a(2) and b(2) will be either side of a right angle of a triangle. C(2) is the long diagonal slope that joins the end of a(2) and c(2) to make a triangle. for example: If a(2) is 4cm long and b(2) is 5cm long this will be the equation to solve the area of c(2) a(2) + b(2) = c(2) 4(2) + 5(2) = c(2) 16 + 25 = c(2) 41 = c(2) You get 41 by adding 16 & 25 and then you find the square root of 41 6.40312 = C√ So the area of c(2) is 6.40312cm Hope this helps :)



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https://math.answers.com/math-and-arithmetic/How_is_math_used_with_the_pythagorean_theorem

How is math used with the pythagorean theorem? - Answers

It is used to measure the area of c2 which will be the diagonal slope for ANY triangle. The equation will always be a2 + b2 = c2 (2)= squared a(2) and b(2) will be either side of a right angle of a triangle. C(2) is the long diagonal slope that joins the end of a(2) and c(2) to make a triangle. for example: If a(2) is 4cm long and b(2) is 5cm long this will be the equation to solve the area of c(2) a(2) + b(2) = c(2) 4(2) + 5(2) = c(2) 16 + 25 = c(2) 41 = c(2) You get 41 by adding 16 & 25 and then you find the square root of 41 6.40312 = C√ So the area of c(2) is 6.40312cm Hope this helps :)

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      It is used to measure the area of c2 which will be the diagonal slope for ANY triangle. The equation will always be a2 + b2 = c2 (2)= squared a(2) and b(2) will be either side of a right angle of a triangle. C(2) is the long diagonal slope that joins the end of a(2) and c(2) to make a triangle. for example: If a(2) is 4cm long and b(2) is 5cm long this will be the equation to solve the area of c(2) a(2) + b(2) = c(2) 4(2) + 5(2) = c(2) 16 + 25 = c(2) 41 = c(2) You get 41 by adding 16 & 25 and then you find the square root of 41 6.40312 = C√ So the area of c(2) is 6.40312cm Hope this helps :)

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