math.answers.com/math-and-arithmetic/How_long_does_it_take_to_fall_9.6_meters

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/How_long_does_it_take_to_fall_9.6_meters

How long does it take to fall 9.6 meters? - Answers

Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.If V0= 0 and a = 9.8 m/s2, then: 9.6 m = (4.9 m/s2)*t2t2 = (9.6 m) / (4.9 m/s2) = 1.9592 s2 ; t = sqrt(1.9592 s2) = 1.3997 seconds



Bing

How long does it take to fall 9.6 meters? - Answers

https://math.answers.com/math-and-arithmetic/How_long_does_it_take_to_fall_9.6_meters

Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.If V0= 0 and a = 9.8 m/s2, then: 9.6 m = (4.9 m/s2)*t2t2 = (9.6 m) / (4.9 m/s2) = 1.9592 s2 ; t = sqrt(1.9592 s2) = 1.3997 seconds



DuckDuckGo

https://math.answers.com/math-and-arithmetic/How_long_does_it_take_to_fall_9.6_meters

How long does it take to fall 9.6 meters? - Answers

Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.If V0= 0 and a = 9.8 m/s2, then: 9.6 m = (4.9 m/s2)*t2t2 = (9.6 m) / (4.9 m/s2) = 1.9592 s2 ; t = sqrt(1.9592 s2) = 1.3997 seconds

  • General Meta Tags

    22
    • title
      How long does it take to fall 9.6 meters? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1

  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      Assuming on the Earth where g = 9.8 m/sec2 and we neglect air drag, and the object started at rest (zero initial velocity) then:d = V0*t + (a*t2)/2; with d = distance, V0 = initial velocity, a = acceleration, and t = time.If V0= 0 and a = 9.8 m/s2, then: 9.6 m = (4.9 m/s2)*t2t2 = (9.6 m) / (4.9 m/s2) = 1.9592 s2 ; t = sqrt(1.9592 s2) = 1.3997 seconds

  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image

  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/How_long_does_it_take_to_fall_9.6_meters
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58