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How many combinations are there in a set of 4 numbers? - Answers

In a set of 4 numbers, the number of combinations depends on how many numbers you want to choose from that set. If you want to choose all 4 numbers, there is only 1 combination. If you choose 2 numbers from the set, the number of combinations is calculated using the formula ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), which in this case would be ( \binom{4}{2} = 6 ). For different values of r (choosing 1, 2, or 3 numbers), the combinations would be 4, 6, and 4 respectively.



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How many combinations are there in a set of 4 numbers? - Answers

https://math.answers.com/math-and-arithmetic/How_many_combinations_are_there_in_a_set_of_4_numbers

In a set of 4 numbers, the number of combinations depends on how many numbers you want to choose from that set. If you want to choose all 4 numbers, there is only 1 combination. If you choose 2 numbers from the set, the number of combinations is calculated using the formula ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), which in this case would be ( \binom{4}{2} = 6 ). For different values of r (choosing 1, 2, or 3 numbers), the combinations would be 4, 6, and 4 respectively.



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https://math.answers.com/math-and-arithmetic/How_many_combinations_are_there_in_a_set_of_4_numbers

How many combinations are there in a set of 4 numbers? - Answers

In a set of 4 numbers, the number of combinations depends on how many numbers you want to choose from that set. If you want to choose all 4 numbers, there is only 1 combination. If you choose 2 numbers from the set, the number of combinations is calculated using the formula ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), which in this case would be ( \binom{4}{2} = 6 ). For different values of r (choosing 1, 2, or 3 numbers), the combinations would be 4, 6, and 4 respectively.

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      In a set of 4 numbers, the number of combinations depends on how many numbers you want to choose from that set. If you want to choose all 4 numbers, there is only 1 combination. If you choose 2 numbers from the set, the number of combinations is calculated using the formula ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), which in this case would be ( \binom{4}{2} = 6 ). For different values of r (choosing 1, 2, or 3 numbers), the combinations would be 4, 6, and 4 respectively.

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