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How many different integer values of x satisfy this inequality 8x 2-xx? - Answers

To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.



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How many different integer values of x satisfy this inequality 8x 2-xx? - Answers

https://math.answers.com/math-and-arithmetic/How_many_different_integer_values_of_x_satisfy_this_inequality_8x_2-xx

To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.



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https://math.answers.com/math-and-arithmetic/How_many_different_integer_values_of_x_satisfy_this_inequality_8x_2-xx

How many different integer values of x satisfy this inequality 8x 2-xx? - Answers

To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.

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      To solve the inequality (8x^2 - x < 0), we first factor it as (x(8x - 1) < 0). The critical points are (x = 0) and (x = \frac{1}{8}). Analyzing the sign of the product in the intervals determined by these points, we find that the inequality holds for (0 < x < \frac{1}{8}). Since there are no integer values of (x) in this interval, the number of different integer values of (x) that satisfy the inequality is zero.

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