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How many doubles and trebles from 16 selections? - Answers

To calculate the number of doubles and trebles from 16 selections, you can use combinations. For doubles, the number of ways to choose 2 selections from 16 is given by the combination formula ( \binom{n}{r} ), which is ( \binom{16}{2} = \frac{16!}{2!(16-2)!} = 120 ). For trebles, the number of ways to choose 3 selections from 16 is ( \binom{16}{3} = \frac{16!}{3!(16-3)!} = 560 ). Thus, there are 120 doubles and 560 trebles from 16 selections.



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How many doubles and trebles from 16 selections? - Answers

https://math.answers.com/math-and-arithmetic/How_many_doubles_and_trebles_from_16_selections

To calculate the number of doubles and trebles from 16 selections, you can use combinations. For doubles, the number of ways to choose 2 selections from 16 is given by the combination formula ( \binom{n}{r} ), which is ( \binom{16}{2} = \frac{16!}{2!(16-2)!} = 120 ). For trebles, the number of ways to choose 3 selections from 16 is ( \binom{16}{3} = \frac{16!}{3!(16-3)!} = 560 ). Thus, there are 120 doubles and 560 trebles from 16 selections.



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https://math.answers.com/math-and-arithmetic/How_many_doubles_and_trebles_from_16_selections

How many doubles and trebles from 16 selections? - Answers

To calculate the number of doubles and trebles from 16 selections, you can use combinations. For doubles, the number of ways to choose 2 selections from 16 is given by the combination formula ( \binom{n}{r} ), which is ( \binom{16}{2} = \frac{16!}{2!(16-2)!} = 120 ). For trebles, the number of ways to choose 3 selections from 16 is ( \binom{16}{3} = \frac{16!}{3!(16-3)!} = 560 ). Thus, there are 120 doubles and 560 trebles from 16 selections.

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      To calculate the number of doubles and trebles from 16 selections, you can use combinations. For doubles, the number of ways to choose 2 selections from 16 is given by the combination formula ( \binom{n}{r} ), which is ( \binom{16}{2} = \frac{16!}{2!(16-2)!} = 120 ). For trebles, the number of ways to choose 3 selections from 16 is ( \binom{16}{3} = \frac{16!}{3!(16-3)!} = 560 ). Thus, there are 120 doubles and 560 trebles from 16 selections.

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