How many grams are in 8.2 x 1022 molecules f N2l6? - Answers

To find the mass in grams of 8.2 x 10^22 molecules of N2l6, we first need to determine the molar mass of N2l6. The molar mass is calculated by adding the atomic masses of nitrogen (N) and iodine (l) in the formula. N has an Atomic Mass of approximately 14 g/mol and I has about 127 g/mol; thus, N2l6 has a molar mass of (2 * 14) + (6 * 127) = 868 g/mol. Next, we convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol): 8.2 x 10^22 molecules * (1 mol / 6.022 x 10^23 molecules) ≈ 0.136 moles. Finally, we multiply the number of moles by the molar mass: 0.136 moles * 868 g/mol ≈ 118.5 grams. Therefore, there are approximately 118.5 grams of N2l6 in 8.2 x 10^22 molecules.