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How many odd numbers between 1 and 125? - Answers

To find the number of odd numbers between 1 and 125, we note that the odd numbers in this range form an arithmetic sequence starting at 1 and ending at 125, with a common difference of 2. The sequence can be expressed as 1, 3, 5, ..., 125. The number of terms in this sequence can be calculated using the formula for the nth term of an arithmetic sequence: ( n = \frac{(last - first)}{difference} + 1 ). Substituting the values, we get ( n = \frac{(125 - 1)}{2} + 1 = 63 ). Thus, there are 63 odd numbers between 1 and 125.



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How many odd numbers between 1 and 125? - Answers

https://math.answers.com/math-and-arithmetic/How_many_odd_numbers_between_1_and_125

To find the number of odd numbers between 1 and 125, we note that the odd numbers in this range form an arithmetic sequence starting at 1 and ending at 125, with a common difference of 2. The sequence can be expressed as 1, 3, 5, ..., 125. The number of terms in this sequence can be calculated using the formula for the nth term of an arithmetic sequence: ( n = \frac{(last - first)}{difference} + 1 ). Substituting the values, we get ( n = \frac{(125 - 1)}{2} + 1 = 63 ). Thus, there are 63 odd numbers between 1 and 125.



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https://math.answers.com/math-and-arithmetic/How_many_odd_numbers_between_1_and_125

How many odd numbers between 1 and 125? - Answers

To find the number of odd numbers between 1 and 125, we note that the odd numbers in this range form an arithmetic sequence starting at 1 and ending at 125, with a common difference of 2. The sequence can be expressed as 1, 3, 5, ..., 125. The number of terms in this sequence can be calculated using the formula for the nth term of an arithmetic sequence: ( n = \frac{(last - first)}{difference} + 1 ). Substituting the values, we get ( n = \frac{(125 - 1)}{2} + 1 = 63 ). Thus, there are 63 odd numbers between 1 and 125.

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      To find the number of odd numbers between 1 and 125, we note that the odd numbers in this range form an arithmetic sequence starting at 1 and ending at 125, with a common difference of 2. The sequence can be expressed as 1, 3, 5, ..., 125. The number of terms in this sequence can be calculated using the formula for the nth term of an arithmetic sequence: ( n = \frac{(last - first)}{difference} + 1 ). Substituting the values, we get ( n = \frac{(125 - 1)}{2} + 1 = 63 ). Thus, there are 63 odd numbers between 1 and 125.

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