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How many rectangles have the same perimator as area? - Answers
Preimeter is a measure of length, area ... well, of area. You can't really compare the perimeter and the area. If both are equal in one unit (like centimeter vs. square centimeter), they won't be equal in another unit (like meters and square meters). Anyway, to be numerically equal, you must solve the equation area = perimeter. Assuming dimensions of a times b, the equation becomes: ab = 2(a+b). Solving for a: ab = 2a + 2b ab - 2a = 2b a(b-2) = 2b a = 2b / (b-2) With this last equation, you can substitute any value for b, and get the corresponding value for a. It seems there are infinitely many solutions.
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How many rectangles have the same perimator as area? - Answers
Preimeter is a measure of length, area ... well, of area. You can't really compare the perimeter and the area. If both are equal in one unit (like centimeter vs. square centimeter), they won't be equal in another unit (like meters and square meters). Anyway, to be numerically equal, you must solve the equation area = perimeter. Assuming dimensions of a times b, the equation becomes: ab = 2(a+b). Solving for a: ab = 2a + 2b ab - 2a = 2b a(b-2) = 2b a = 2b / (b-2) With this last equation, you can substitute any value for b, and get the corresponding value for a. It seems there are infinitely many solutions.
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How many rectangles have the same perimator as area? - Answers
Preimeter is a measure of length, area ... well, of area. You can't really compare the perimeter and the area. If both are equal in one unit (like centimeter vs. square centimeter), they won't be equal in another unit (like meters and square meters). Anyway, to be numerically equal, you must solve the equation area = perimeter. Assuming dimensions of a times b, the equation becomes: ab = 2(a+b). Solving for a: ab = 2a + 2b ab - 2a = 2b a(b-2) = 2b a = 2b / (b-2) With this last equation, you can substitute any value for b, and get the corresponding value for a. It seems there are infinitely many solutions.
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