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How many ways can you arrange 6 objects? - Answers

Assuming that by "arrange" you mean "order" (if you really mean "arrange", there are infinitely many possible ways to arrange even just two objects; you could separate them by 1 inch, or by 2 inches, or by 3.14159265... inches, and that's without even getting into left vs. right or above vs. below or at an angle of x degrees from horizontal) ...You can choose any of the 6 to be first, any of the remaining 5 to be second, any of the remaining 4 to be third, and so on, down to the last one where you have no choice because it's the only one left.That means there are 6x5x4x3x2(x1), or 6! = 720 possible orderings.



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How many ways can you arrange 6 objects? - Answers

https://math.answers.com/math-and-arithmetic/How_many_ways_can_you_arrange_6_objects

Assuming that by "arrange" you mean "order" (if you really mean "arrange", there are infinitely many possible ways to arrange even just two objects; you could separate them by 1 inch, or by 2 inches, or by 3.14159265... inches, and that's without even getting into left vs. right or above vs. below or at an angle of x degrees from horizontal) ...You can choose any of the 6 to be first, any of the remaining 5 to be second, any of the remaining 4 to be third, and so on, down to the last one where you have no choice because it's the only one left.That means there are 6x5x4x3x2(x1), or 6! = 720 possible orderings.



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https://math.answers.com/math-and-arithmetic/How_many_ways_can_you_arrange_6_objects

How many ways can you arrange 6 objects? - Answers

Assuming that by "arrange" you mean "order" (if you really mean "arrange", there are infinitely many possible ways to arrange even just two objects; you could separate them by 1 inch, or by 2 inches, or by 3.14159265... inches, and that's without even getting into left vs. right or above vs. below or at an angle of x degrees from horizontal) ...You can choose any of the 6 to be first, any of the remaining 5 to be second, any of the remaining 4 to be third, and so on, down to the last one where you have no choice because it's the only one left.That means there are 6x5x4x3x2(x1), or 6! = 720 possible orderings.

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      Assuming that by "arrange" you mean "order" (if you really mean "arrange", there are infinitely many possible ways to arrange even just two objects; you could separate them by 1 inch, or by 2 inches, or by 3.14159265... inches, and that's without even getting into left vs. right or above vs. below or at an angle of x degrees from horizontal) ...You can choose any of the 6 to be first, any of the remaining 5 to be second, any of the remaining 4 to be third, and so on, down to the last one where you have no choice because it's the only one left.That means there are 6x5x4x3x2(x1), or 6! = 720 possible orderings.

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