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How may cubic yard concert needed for 4'x55'x4? - Answers

Just multiply the numbers together. 4 X 55 X 4 (assuming they are all feet). = 4080 cubic feet. Now, 27 cubic feet per cubic yard so 4080/27 = 151.1 cu yds. But if the last number in the problem was 4 inches (not feet) then the above answer is 12 times too much. [and 4 inches is a fair thickness for a path or drive] so 151.1/12 = 12.59 cu yards.



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How may cubic yard concert needed for 4'x55'x4? - Answers

https://math.answers.com/math-and-arithmetic/How_may_cubic_yard_concert_needed_for_4'x55'x4

Just multiply the numbers together. 4 X 55 X 4 (assuming they are all feet). = 4080 cubic feet. Now, 27 cubic feet per cubic yard so 4080/27 = 151.1 cu yds. But if the last number in the problem was 4 inches (not feet) then the above answer is 12 times too much. [and 4 inches is a fair thickness for a path or drive] so 151.1/12 = 12.59 cu yards.



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https://math.answers.com/math-and-arithmetic/How_may_cubic_yard_concert_needed_for_4'x55'x4

How may cubic yard concert needed for 4'x55'x4? - Answers

Just multiply the numbers together. 4 X 55 X 4 (assuming they are all feet). = 4080 cubic feet. Now, 27 cubic feet per cubic yard so 4080/27 = 151.1 cu yds. But if the last number in the problem was 4 inches (not feet) then the above answer is 12 times too much. [and 4 inches is a fair thickness for a path or drive] so 151.1/12 = 12.59 cu yards.

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      Just multiply the numbers together. 4 X 55 X 4 (assuming they are all feet). = 4080 cubic feet. Now, 27 cubic feet per cubic yard so 4080/27 = 151.1 cu yds. But if the last number in the problem was 4 inches (not feet) then the above answer is 12 times too much. [and 4 inches is a fair thickness for a path or drive] so 151.1/12 = 12.59 cu yards.

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