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How you can solve equations with graphing? - Answers
An equation to be graphed must be written (or must be entered in a graphing calculator) in the form y = ..., that is, y must be expressed as a function of x. After a graph is displayed in your graphing calculator, you can use the calculator's TRACE feature to find the x-intercept(s) (a point that the graph intersects the x-axis where y = 0). Move the TRACE cursor to a point just below the x-axis and press ENTER, MOVE the TRACE cursor to a point just above the x-axis and press ENTER, press ENTER again. In this way you can find the x-intercept(s). Thus, each x-intercept of the function is a real solution of the equation to any desired degree of accuracy.
Bing
How you can solve equations with graphing? - Answers
An equation to be graphed must be written (or must be entered in a graphing calculator) in the form y = ..., that is, y must be expressed as a function of x. After a graph is displayed in your graphing calculator, you can use the calculator's TRACE feature to find the x-intercept(s) (a point that the graph intersects the x-axis where y = 0). Move the TRACE cursor to a point just below the x-axis and press ENTER, MOVE the TRACE cursor to a point just above the x-axis and press ENTER, press ENTER again. In this way you can find the x-intercept(s). Thus, each x-intercept of the function is a real solution of the equation to any desired degree of accuracy.
DuckDuckGo
How you can solve equations with graphing? - Answers
An equation to be graphed must be written (or must be entered in a graphing calculator) in the form y = ..., that is, y must be expressed as a function of x. After a graph is displayed in your graphing calculator, you can use the calculator's TRACE feature to find the x-intercept(s) (a point that the graph intersects the x-axis where y = 0). Move the TRACE cursor to a point just below the x-axis and press ENTER, MOVE the TRACE cursor to a point just above the x-axis and press ENTER, press ENTER again. In this way you can find the x-intercept(s). Thus, each x-intercept of the function is a real solution of the equation to any desired degree of accuracy.
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