math.answers.com/math-and-arithmetic/How_you_find_the_intercepts_using_the_polynomial

Preview meta tags from the math.answers.com website.

Linked Hostnames

8

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/How_you_find_the_intercepts_using_the_polynomial

How you find the intercepts using the polynomial? - Answers

I'm assuming you're talking about the equation for a graph here. If you think about the axes on the graph, the y-axis occurs at x = 0, and the x-axis at y = 0. So, to find out where the line crosses the y-axis (or y-intercept), simply set x = 0 in the equation. Example: y = 3x+7 when x = 0, y = 3 x 0 + 7, so y = 7 therefore the y-intercept is 7 To find the x-intercept, simply set y = 0 in the equation. This can be more difficult, especially if it has more than x cubed in it (there are formulae that can be used to solve polynomials, but they can get complicated). Examples: y = 3x+7 when y = 0, 0 = 3x+7, so 3x = -7, and thus x = -7/3 therefore the x-intercept is -7/3 y = x^2+6x+8 when y = 0, x^2+6x+8 = 0, therefore x = -2 or -4 therefore the x-intercepts are -2 and -4 y = x^3+9x^2+30x+24 when y = 0, x^3+9x^2+30x+24 = 0, therefore x = -2, -3 or -4 therefore the x-intercepts are -2, -3 and -4



Bing

How you find the intercepts using the polynomial? - Answers

https://math.answers.com/math-and-arithmetic/How_you_find_the_intercepts_using_the_polynomial

I'm assuming you're talking about the equation for a graph here. If you think about the axes on the graph, the y-axis occurs at x = 0, and the x-axis at y = 0. So, to find out where the line crosses the y-axis (or y-intercept), simply set x = 0 in the equation. Example: y = 3x+7 when x = 0, y = 3 x 0 + 7, so y = 7 therefore the y-intercept is 7 To find the x-intercept, simply set y = 0 in the equation. This can be more difficult, especially if it has more than x cubed in it (there are formulae that can be used to solve polynomials, but they can get complicated). Examples: y = 3x+7 when y = 0, 0 = 3x+7, so 3x = -7, and thus x = -7/3 therefore the x-intercept is -7/3 y = x^2+6x+8 when y = 0, x^2+6x+8 = 0, therefore x = -2 or -4 therefore the x-intercepts are -2 and -4 y = x^3+9x^2+30x+24 when y = 0, x^3+9x^2+30x+24 = 0, therefore x = -2, -3 or -4 therefore the x-intercepts are -2, -3 and -4



DuckDuckGo

https://math.answers.com/math-and-arithmetic/How_you_find_the_intercepts_using_the_polynomial

How you find the intercepts using the polynomial? - Answers

I'm assuming you're talking about the equation for a graph here. If you think about the axes on the graph, the y-axis occurs at x = 0, and the x-axis at y = 0. So, to find out where the line crosses the y-axis (or y-intercept), simply set x = 0 in the equation. Example: y = 3x+7 when x = 0, y = 3 x 0 + 7, so y = 7 therefore the y-intercept is 7 To find the x-intercept, simply set y = 0 in the equation. This can be more difficult, especially if it has more than x cubed in it (there are formulae that can be used to solve polynomials, but they can get complicated). Examples: y = 3x+7 when y = 0, 0 = 3x+7, so 3x = -7, and thus x = -7/3 therefore the x-intercept is -7/3 y = x^2+6x+8 when y = 0, x^2+6x+8 = 0, therefore x = -2 or -4 therefore the x-intercepts are -2 and -4 y = x^3+9x^2+30x+24 when y = 0, x^3+9x^2+30x+24 = 0, therefore x = -2, -3 or -4 therefore the x-intercepts are -2, -3 and -4

  • General Meta Tags

    22
    • title
      How you find the intercepts using the polynomial? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1
  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      I'm assuming you're talking about the equation for a graph here. If you think about the axes on the graph, the y-axis occurs at x = 0, and the x-axis at y = 0. So, to find out where the line crosses the y-axis (or y-intercept), simply set x = 0 in the equation. Example: y = 3x+7 when x = 0, y = 3 x 0 + 7, so y = 7 therefore the y-intercept is 7 To find the x-intercept, simply set y = 0 in the equation. This can be more difficult, especially if it has more than x cubed in it (there are formulae that can be used to solve polynomials, but they can get complicated). Examples: y = 3x+7 when y = 0, 0 = 3x+7, so 3x = -7, and thus x = -7/3 therefore the x-intercept is -7/3 y = x^2+6x+8 when y = 0, x^2+6x+8 = 0, therefore x = -2 or -4 therefore the x-intercepts are -2 and -4 y = x^3+9x^2+30x+24 when y = 0, x^3+9x^2+30x+24 = 0, therefore x = -2, -3 or -4 therefore the x-intercepts are -2, -3 and -4
  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image
  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/How_you_find_the_intercepts_using_the_polynomial
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

58