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if one end point is at (-5,-6) and the midpoint is at (1,1) whats the endpoint? - Answers

M = ((x1+x2)/2, (y1+y2)/2) (1,1) = ((-5+x)/2, (-6+y)/2) (-5+x))/2 = 1, (-6+y)/2 = 1 -5 + x = 2, -6+y = 2 x = 7, y = 8 The end point is (7,8)



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if one end point is at (-5,-6) and the midpoint is at (1,1) whats the endpoint? - Answers

https://math.answers.com/math-and-arithmetic/If-one-end-point-is-at-5-6-and-the-midpoint-is-at-11-whats-the-endpoint

M = ((x1+x2)/2, (y1+y2)/2) (1,1) = ((-5+x)/2, (-6+y)/2) (-5+x))/2 = 1, (-6+y)/2 = 1 -5 + x = 2, -6+y = 2 x = 7, y = 8 The end point is (7,8)



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https://math.answers.com/math-and-arithmetic/If-one-end-point-is-at-5-6-and-the-midpoint-is-at-11-whats-the-endpoint

if one end point is at (-5,-6) and the midpoint is at (1,1) whats the endpoint? - Answers

M = ((x1+x2)/2, (y1+y2)/2) (1,1) = ((-5+x)/2, (-6+y)/2) (-5+x))/2 = 1, (-6+y)/2 = 1 -5 + x = 2, -6+y = 2 x = 7, y = 8 The end point is (7,8)

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      M = ((x1+x2)/2, (y1+y2)/2) (1,1) = ((-5+x)/2, (-6+y)/2) (-5+x))/2 = 1, (-6+y)/2 = 1 -5 + x = 2, -6+y = 2 x = 7, y = 8 The end point is (7,8)

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