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If the joint probability distribution of X and Y is given by? - Answers

(i) P(X <= 2, Y = 1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = (0+1)/30 + (1+1)/30 + (2+1)/30 = 6/30 = 1/5. (ii) P(X + Y = 4) = P(X=2, Y=2) + P(X=3, Y=1) = (2+2)/30 + (3+1)/30 = 8/30 = 4/15.



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If the joint probability distribution of X and Y is given by? - Answers

https://math.answers.com/math-and-arithmetic/If_the_joint_probability_distribution_of_X_and_Y_is_given_by

(i) P(X <= 2, Y = 1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = (0+1)/30 + (1+1)/30 + (2+1)/30 = 6/30 = 1/5. (ii) P(X + Y = 4) = P(X=2, Y=2) + P(X=3, Y=1) = (2+2)/30 + (3+1)/30 = 8/30 = 4/15.



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https://math.answers.com/math-and-arithmetic/If_the_joint_probability_distribution_of_X_and_Y_is_given_by

If the joint probability distribution of X and Y is given by? - Answers

(i) P(X <= 2, Y = 1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = (0+1)/30 + (1+1)/30 + (2+1)/30 = 6/30 = 1/5. (ii) P(X + Y = 4) = P(X=2, Y=2) + P(X=3, Y=1) = (2+2)/30 + (3+1)/30 = 8/30 = 4/15.

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      (i) P(X <= 2, Y = 1) = P(X=0, Y=1) + P(X=1, Y=1) + P(X=2, Y=1) = (0+1)/30 + (1+1)/30 + (2+1)/30 = 6/30 = 1/5. (ii) P(X + Y = 4) = P(X=2, Y=2) + P(X=3, Y=1) = (2+2)/30 + (3+1)/30 = 8/30 = 4/15.

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