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Is The composition of an odd function and an odd function even? - Answers

The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.



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Is The composition of an odd function and an odd function even? - Answers

https://math.answers.com/math-and-arithmetic/Is_The_composition_of_an_odd_function_and_an_odd_function_even

The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.



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https://math.answers.com/math-and-arithmetic/Is_The_composition_of_an_odd_function_and_an_odd_function_even

Is The composition of an odd function and an odd function even? - Answers

The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.

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      The composition of two odd functions is an even function. If ( f(x) ) and ( g(x) ) are both odd, then for their composition ( (f \circ g)(x) = f(g(x)) ), we have ( (f \circ g)(-x) = f(g(-x)) = f(-g(x)) = -f(g(x)) = -(f \circ g)(x) ). Thus, ( (f \circ g)(x) ) satisfies the definition of an even function.

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