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https://math.answers.com/math-and-arithmetic/Is_the_product_of_two_irrational_numbers_is_an_integer

Is the product of two irrational numbers is an integer? - Answers

It can be, but need not be. [sqrt(5)+sqrt(2)] and [sqrt(5)-sqrt(2)] are both irrational. Their product is 5-2 = 3. The two numbers are conjugates of one another and the property that their product is an integer is used to rationalise denominator of surds.



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Is the product of two irrational numbers is an integer? - Answers

https://math.answers.com/math-and-arithmetic/Is_the_product_of_two_irrational_numbers_is_an_integer

It can be, but need not be. [sqrt(5)+sqrt(2)] and [sqrt(5)-sqrt(2)] are both irrational. Their product is 5-2 = 3. The two numbers are conjugates of one another and the property that their product is an integer is used to rationalise denominator of surds.



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https://math.answers.com/math-and-arithmetic/Is_the_product_of_two_irrational_numbers_is_an_integer

Is the product of two irrational numbers is an integer? - Answers

It can be, but need not be. [sqrt(5)+sqrt(2)] and [sqrt(5)-sqrt(2)] are both irrational. Their product is 5-2 = 3. The two numbers are conjugates of one another and the property that their product is an integer is used to rationalise denominator of surds.

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      It can be, but need not be. [sqrt(5)+sqrt(2)] and [sqrt(5)-sqrt(2)] are both irrational. Their product is 5-2 = 3. The two numbers are conjugates of one another and the property that their product is an integer is used to rationalise denominator of surds.

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