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https://math.answers.com/math-and-arithmetic/Transform_between_Cartesian_and_polar_coordinates

Transform between Cartesian and polar coordinates? - Answers

for whatever point (x, y): r= sqrt( x2+ y2 ) from pythagorean theorem. basic trig function since the x and y axes are perpendicular to each other: tan theta = y/x (opposite over adjacent) theta = tan-1 (y/x) (r, theta) ----> ( sqrt( x2+ y2 ), tan-1 (y/x) )



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Transform between Cartesian and polar coordinates? - Answers

https://math.answers.com/math-and-arithmetic/Transform_between_Cartesian_and_polar_coordinates

for whatever point (x, y): r= sqrt( x2+ y2 ) from pythagorean theorem. basic trig function since the x and y axes are perpendicular to each other: tan theta = y/x (opposite over adjacent) theta = tan-1 (y/x) (r, theta) ----> ( sqrt( x2+ y2 ), tan-1 (y/x) )



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https://math.answers.com/math-and-arithmetic/Transform_between_Cartesian_and_polar_coordinates

Transform between Cartesian and polar coordinates? - Answers

for whatever point (x, y): r= sqrt( x2+ y2 ) from pythagorean theorem. basic trig function since the x and y axes are perpendicular to each other: tan theta = y/x (opposite over adjacent) theta = tan-1 (y/x) (r, theta) ----> ( sqrt( x2+ y2 ), tan-1 (y/x) )

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      for whatever point (x, y): r= sqrt( x2+ y2 ) from pythagorean theorem. basic trig function since the x and y axes are perpendicular to each other: tan theta = y/x (opposite over adjacent) theta = tan-1 (y/x) (r, theta) ----> ( sqrt( x2+ y2 ), tan-1 (y/x) )

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