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https://math.answers.com/other-math/Are_all_odd_square_roots_the_square_roots_of_odd_numbers

Are all odd square roots the square roots of odd numbers? - Answers

Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.



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Are all odd square roots the square roots of odd numbers? - Answers

https://math.answers.com/other-math/Are_all_odd_square_roots_the_square_roots_of_odd_numbers

Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.



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https://math.answers.com/other-math/Are_all_odd_square_roots_the_square_roots_of_odd_numbers

Are all odd square roots the square roots of odd numbers? - Answers

Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.

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      Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.

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