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How many diagonals are there in a 35-sided polygon? - Answers

The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560

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How many diagonals are there in a 35-sided polygon? - Answers

https://math.answers.com/other-math/How_many_diagonals_are_there_in_a_35-sided_polygon

The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560

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https://math.answers.com/other-math/How_many_diagonals_are_there_in_a_35-sided_polygon

How many diagonals are there in a 35-sided polygon? - Answers

The number of diagonals is n(n-1)/2 - n substitute n=35 35(34)/2 - 35 = 560

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