math.answers.com/other-math/How_many_four_digit_numbers_are_there_with_two_repeated_digits
Preview meta tags from the math.answers.com website.
Linked Hostnames
8- 34 links tomath.answers.com
- 18 links towww.answers.com
- 1 link totwitter.com
- 1 link towww.facebook.com
- 1 link towww.instagram.com
- 1 link towww.pinterest.com
- 1 link towww.tiktok.com
- 1 link towww.youtube.com
Thumbnail

Search Engine Appearance
How many four digit numbers are there with two repeated digits? - Answers
xxyz xyxz xyzx yxxz yxzx yzxx if x is the digit that repeats then there are six possible placements of ten digits y must be one of the remaining nine digits and z must be one of the further remaining eight digits so 6x10x9x8 = 4320 (note: this supposes that leading zeros are included)
Bing
How many four digit numbers are there with two repeated digits? - Answers
xxyz xyxz xyzx yxxz yxzx yzxx if x is the digit that repeats then there are six possible placements of ten digits y must be one of the remaining nine digits and z must be one of the further remaining eight digits so 6x10x9x8 = 4320 (note: this supposes that leading zeros are included)
DuckDuckGo
How many four digit numbers are there with two repeated digits? - Answers
xxyz xyxz xyzx yxxz yxzx yzxx if x is the digit that repeats then there are six possible placements of ten digits y must be one of the remaining nine digits and z must be one of the further remaining eight digits so 6x10x9x8 = 4320 (note: this supposes that leading zeros are included)
General Meta Tags
22- titleHow many four digit numbers are there with two repeated digits? - Answers
- charsetutf-8
- Content-Typetext/html; charset=utf-8
- viewportminimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
- X-UA-CompatibleIE=edge,chrome=1
Open Graph Meta Tags
7- og:imagehttps://st.answers.com/html_test_assets/Answers_Blue.jpeg
- og:image:width900
- og:image:height900
- og:site_nameAnswers
- og:descriptionxxyz xyxz xyzx yxxz yxzx yzxx if x is the digit that repeats then there are six possible placements of ten digits y must be one of the remaining nine digits and z must be one of the further remaining eight digits so 6x10x9x8 = 4320 (note: this supposes that leading zeros are included)
Twitter Meta Tags
1- twitter:cardsummary_large_image
Link Tags
16- alternatehttps://www.answers.com/feed.rss
- apple-touch-icon/icons/180x180.png
- canonicalhttps://math.answers.com/other-math/How_many_four_digit_numbers_are_there_with_two_repeated_digits
- icon/favicon.svg
- icon/icons/16x16.png
Links
58- https://math.answers.com
- https://math.answers.com/other-math/A_Quadrilateral_with_4_right_angles
- https://math.answers.com/other-math/Draw_a_flow_chart_that_will_compute_and_print_the_sum_and_average_of_3_numbers
- https://math.answers.com/other-math/Four_hundred_twenty-five_thousand
- https://math.answers.com/other-math/How_do_you_solve_the_problem_for_63.39_divided_by_0.24