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Self-Counting Sequence -- from Wolfram MathWorld

The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).



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Self-Counting Sequence -- from Wolfram MathWorld

https://mathworld.wolfram.com/Self-CountingSequence.html

The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).



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https://mathworld.wolfram.com/Self-CountingSequence.html

Self-Counting Sequence -- from Wolfram MathWorld

The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).

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      Self-Counting Sequence -- from Wolfram MathWorld
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      Self-Counting Sequence
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      The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).
    • description
      The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).
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      Self-Counting Sequence -- from Wolfram MathWorld
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      The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).
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      The sequence 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, ... (OEIS A002024) consisting of 1 copy of 1, 2 copies of 2, 3 copies of 3, and so on. Surprisingly, there exist simple formulas for the nth term a(n), a(n) = |_1/2+sqrt(2n)_| (1) = [1/2(sqrt(8n+1)-1)], (2) where |_x_| is the floor function and [x] is the ceiling function (Graham et al. 1994, p. 97). The sequence is also given by the recursive sequence a(n)=1+a(n-a(n-1)) (3) (Wolfram 2002, p. 129).
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