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Age problem involving quadratic equations with answers? - Answers

in quadratic equation it must be in standard form, ax^2 + bx + c = 0. Jenny is five years older than Marian. In three years, the product of her age and Marian's age five years ago will be 90 years. Find their present age. Solution: Let x= Marian's present age x + 5= Jenny's present age The working



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Age problem involving quadratic equations with answers? - Answers

https://math.answers.com/algebra/Age_problem_involving_quadratic_equations_with_answers

in quadratic equation it must be in standard form, ax^2 + bx + c = 0. Jenny is five years older than Marian. In three years, the product of her age and Marian's age five years ago will be 90 years. Find their present age. Solution: Let x= Marian's present age x + 5= Jenny's present age The working



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https://math.answers.com/algebra/Age_problem_involving_quadratic_equations_with_answers

Age problem involving quadratic equations with answers? - Answers

in quadratic equation it must be in standard form, ax^2 + bx + c = 0. Jenny is five years older than Marian. In three years, the product of her age and Marian's age five years ago will be 90 years. Find their present age. Solution: Let x= Marian's present age x + 5= Jenny's present age The working

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      in quadratic equation it must be in standard form, ax^2 + bx + c = 0. Jenny is five years older than Marian. In three years, the product of her age and Marian's age five years ago will be 90 years. Find their present age. Solution: Let x= Marian's present age x + 5= Jenny's present age The working

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