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Factor of the trinomial 8x2 -12x - 8? - Answers

8x2 - 12x - 8 = 4 (2x2 - 3x - 2) = 4 (2x2 + x - 4x - 2) = 4 (x (2x + 1) - 2 (2x + 1)) = 4 (x - 2) (2x + 1).



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Factor of the trinomial 8x2 -12x - 8? - Answers

https://math.answers.com/algebra/Factor_of_the_trinomial_8x2_-12x_-_8

8x2 - 12x - 8 = 4 (2x2 - 3x - 2) = 4 (2x2 + x - 4x - 2) = 4 (x (2x + 1) - 2 (2x + 1)) = 4 (x - 2) (2x + 1).



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https://math.answers.com/algebra/Factor_of_the_trinomial_8x2_-12x_-_8

Factor of the trinomial 8x2 -12x - 8? - Answers

8x2 - 12x - 8 = 4 (2x2 - 3x - 2) = 4 (2x2 + x - 4x - 2) = 4 (x (2x + 1) - 2 (2x + 1)) = 4 (x - 2) (2x + 1).

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      8x2 - 12x - 8 = 4 (2x2 - 3x - 2) = 4 (2x2 + x - 4x - 2) = 4 (x (2x + 1) - 2 (2x + 1)) = 4 (x - 2) (2x + 1).

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