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Factor the polynomial x2-7x plus 6? - Answers

x2 -7x +6=0 can be factorised by looking at the 7 and the 6 and looking for two numbers that can both add to give -7 and can multiply to give +6. Possible factors for (numbers that will multiply to give) 6 are: 2 & 3 1 & 6 Now look at the possible sums from these possible factors: 2+3=5 not 7, and making one or more of these negative still won't result in a sum of 7 so we can rule those out. 1+6=7 Good so far! Now look at the sign. We need a negative 7. If both the 1 and the 6 are negative, it will give -7, which is what we are looking for. -1 x -6 =6 because the two negatives cancel out, which is what we need, so the quadratic can be factorised as: (x-1)(x-6)=0



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Factor the polynomial x2-7x plus 6? - Answers

https://math.answers.com/algebra/Factor_the_polynomial_x2-7x_plus_6

x2 -7x +6=0 can be factorised by looking at the 7 and the 6 and looking for two numbers that can both add to give -7 and can multiply to give +6. Possible factors for (numbers that will multiply to give) 6 are: 2 & 3 1 & 6 Now look at the possible sums from these possible factors: 2+3=5 not 7, and making one or more of these negative still won't result in a sum of 7 so we can rule those out. 1+6=7 Good so far! Now look at the sign. We need a negative 7. If both the 1 and the 6 are negative, it will give -7, which is what we are looking for. -1 x -6 =6 because the two negatives cancel out, which is what we need, so the quadratic can be factorised as: (x-1)(x-6)=0



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https://math.answers.com/algebra/Factor_the_polynomial_x2-7x_plus_6

Factor the polynomial x2-7x plus 6? - Answers

x2 -7x +6=0 can be factorised by looking at the 7 and the 6 and looking for two numbers that can both add to give -7 and can multiply to give +6. Possible factors for (numbers that will multiply to give) 6 are: 2 & 3 1 & 6 Now look at the possible sums from these possible factors: 2+3=5 not 7, and making one or more of these negative still won't result in a sum of 7 so we can rule those out. 1+6=7 Good so far! Now look at the sign. We need a negative 7. If both the 1 and the 6 are negative, it will give -7, which is what we are looking for. -1 x -6 =6 because the two negatives cancel out, which is what we need, so the quadratic can be factorised as: (x-1)(x-6)=0

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      x2 -7x +6=0 can be factorised by looking at the 7 and the 6 and looking for two numbers that can both add to give -7 and can multiply to give +6. Possible factors for (numbers that will multiply to give) 6 are: 2 & 3 1 & 6 Now look at the possible sums from these possible factors: 2+3=5 not 7, and making one or more of these negative still won't result in a sum of 7 so we can rule those out. 1+6=7 Good so far! Now look at the sign. We need a negative 7. If both the 1 and the 6 are negative, it will give -7, which is what we are looking for. -1 x -6 =6 because the two negatives cancel out, which is what we need, so the quadratic can be factorised as: (x-1)(x-6)=0

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