math.answers.com/algebra/Factor_the_polynomial_x2-x-35
Preview meta tags from the math.answers.com website.
Linked Hostnames
9- 29 links tomath.answers.com
- 21 links towww.answers.com
- 1 link toqa.answers.com
- 1 link totwitter.com
- 1 link towww.facebook.com
- 1 link towww.instagram.com
- 1 link towww.pinterest.com
- 1 link towww.tiktok.com
Thumbnail

Search Engine Appearance
Factor the polynomial x2-x-35? - Answers
Every polynomial defines a function, often called P. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function. So, P(x) = x^2 - x - 35 0 = X^2 - x - 35 or, x^2 - x - 35 = 0 We can factor this equation as (x - r1)(x - r2) = 0. Let's find r1 and r2: x^2 - x - 35 = 0 add 35 to both sides; x^2 - x = 35 ad to both sides 1/4 in order to complete the square; x^2 - x + 1/4 = 35 + 1/4 (x - 1/2)2 = 141/4 x - 1/2 = +,- square root of 141/4 x = 1/2 +,- 1/2(square root of 141) x = (1 + square root of 141)/2 or x = (1 - square root of 141)/2 So the factorization is: [x - (1 + square root of 141)/2 ] [x - (1 - square root of 141)/2 ] Check.
Bing
Factor the polynomial x2-x-35? - Answers
Every polynomial defines a function, often called P. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function. So, P(x) = x^2 - x - 35 0 = X^2 - x - 35 or, x^2 - x - 35 = 0 We can factor this equation as (x - r1)(x - r2) = 0. Let's find r1 and r2: x^2 - x - 35 = 0 add 35 to both sides; x^2 - x = 35 ad to both sides 1/4 in order to complete the square; x^2 - x + 1/4 = 35 + 1/4 (x - 1/2)2 = 141/4 x - 1/2 = +,- square root of 141/4 x = 1/2 +,- 1/2(square root of 141) x = (1 + square root of 141)/2 or x = (1 - square root of 141)/2 So the factorization is: [x - (1 + square root of 141)/2 ] [x - (1 - square root of 141)/2 ] Check.
DuckDuckGo
Factor the polynomial x2-x-35? - Answers
Every polynomial defines a function, often called P. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function. So, P(x) = x^2 - x - 35 0 = X^2 - x - 35 or, x^2 - x - 35 = 0 We can factor this equation as (x - r1)(x - r2) = 0. Let's find r1 and r2: x^2 - x - 35 = 0 add 35 to both sides; x^2 - x = 35 ad to both sides 1/4 in order to complete the square; x^2 - x + 1/4 = 35 + 1/4 (x - 1/2)2 = 141/4 x - 1/2 = +,- square root of 141/4 x = 1/2 +,- 1/2(square root of 141) x = (1 + square root of 141)/2 or x = (1 - square root of 141)/2 So the factorization is: [x - (1 + square root of 141)/2 ] [x - (1 - square root of 141)/2 ] Check.
General Meta Tags
22- titleFactor the polynomial x2-x-35? - Answers
- charsetutf-8
- Content-Typetext/html; charset=utf-8
- viewportminimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
- X-UA-CompatibleIE=edge,chrome=1
Open Graph Meta Tags
7- og:imagehttps://st.answers.com/html_test_assets/Answers_Blue.jpeg
- og:image:width900
- og:image:height900
- og:site_nameAnswers
- og:descriptionEvery polynomial defines a function, often called P. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function. So, P(x) = x^2 - x - 35 0 = X^2 - x - 35 or, x^2 - x - 35 = 0 We can factor this equation as (x - r1)(x - r2) = 0. Let's find r1 and r2: x^2 - x - 35 = 0 add 35 to both sides; x^2 - x = 35 ad to both sides 1/4 in order to complete the square; x^2 - x + 1/4 = 35 + 1/4 (x - 1/2)2 = 141/4 x - 1/2 = +,- square root of 141/4 x = 1/2 +,- 1/2(square root of 141) x = (1 + square root of 141)/2 or x = (1 - square root of 141)/2 So the factorization is: [x - (1 + square root of 141)/2 ] [x - (1 - square root of 141)/2 ] Check.
Twitter Meta Tags
1- twitter:cardsummary_large_image
Link Tags
16- alternatehttps://www.answers.com/feed.rss
- apple-touch-icon/icons/180x180.png
- canonicalhttps://math.answers.com/algebra/Factor_the_polynomial_x2-x-35
- icon/favicon.svg
- icon/icons/16x16.png
Links
57- https://math.answers.com
- https://math.answers.com/algebra/A_cube_measuring_2cm_on_each_side_weights_5g_will_it_sink_or_float
- https://math.answers.com/algebra/Factor_the_polynomial_x2-x-35
- https://math.answers.com/algebra/How_can_you_kill_30_sheep_in_5_days_while_killing_only_odd_numbers_everyday
- https://math.answers.com/algebra/How_do_you_add_decimals