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How Do you Graph The Following Equation 4x 3y 12? - Answers
Write this equation in slope-intercept form:4x + 3y = 12 subtract 4x to both sides3y = -4x + 12 divide by 3 to both sidesy = -(4/3)x + 4 since the y intercept is 4, then one point is (0, 4)Let x = 3, then y = 0. So the second point is (3, 0)Let x = -3, then y = 8. So the third point is (-3, 8)Now that you have three points, plot them in a coordinate system and connect those points. The line that passes through these points is the graph of the function y = -(4/3)x + 4.
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How Do you Graph The Following Equation 4x 3y 12? - Answers
Write this equation in slope-intercept form:4x + 3y = 12 subtract 4x to both sides3y = -4x + 12 divide by 3 to both sidesy = -(4/3)x + 4 since the y intercept is 4, then one point is (0, 4)Let x = 3, then y = 0. So the second point is (3, 0)Let x = -3, then y = 8. So the third point is (-3, 8)Now that you have three points, plot them in a coordinate system and connect those points. The line that passes through these points is the graph of the function y = -(4/3)x + 4.
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How Do you Graph The Following Equation 4x 3y 12? - Answers
Write this equation in slope-intercept form:4x + 3y = 12 subtract 4x to both sides3y = -4x + 12 divide by 3 to both sidesy = -(4/3)x + 4 since the y intercept is 4, then one point is (0, 4)Let x = 3, then y = 0. So the second point is (3, 0)Let x = -3, then y = 8. So the third point is (-3, 8)Now that you have three points, plot them in a coordinate system and connect those points. The line that passes through these points is the graph of the function y = -(4/3)x + 4.
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