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How do you add consecutive integers? - Answers

i put in the formula x(x+1)(x+2) and then u go from there but im not that sure myself i cant figure out how to get pass the formula so if anyone knows how to do that please help Response: : If x = starting number : n = ending number : x + (x+1) + (x+2) ... +(n) = : ( (n²+n)/2 ) - ( (x²+x)/2 ) :



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How do you add consecutive integers? - Answers

https://math.answers.com/algebra/How_do_you_add_consecutive_integers

i put in the formula x(x+1)(x+2) and then u go from there but im not that sure myself i cant figure out how to get pass the formula so if anyone knows how to do that please help Response: : If x = starting number : n = ending number : x + (x+1) + (x+2) ... +(n) = : ( (n²+n)/2 ) - ( (x²+x)/2 ) :



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https://math.answers.com/algebra/How_do_you_add_consecutive_integers

How do you add consecutive integers? - Answers

i put in the formula x(x+1)(x+2) and then u go from there but im not that sure myself i cant figure out how to get pass the formula so if anyone knows how to do that please help Response: : If x = starting number : n = ending number : x + (x+1) + (x+2) ... +(n) = : ( (n²+n)/2 ) - ( (x²+x)/2 ) :

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      i put in the formula x(x+1)(x+2) and then u go from there but im not that sure myself i cant figure out how to get pass the formula so if anyone knows how to do that please help Response: : If x = starting number : n = ending number : x + (x+1) + (x+2) ... +(n) = : ( (n²+n)/2 ) - ( (x²+x)/2 ) :

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