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How do you calculate Spearman's rank correlation? - Answers

# State the null hypothesis i.e. "There is no relationship between the two sets of data." # Rank both sets of data from the highest to the lowest. Make sure to check for tied ranks. # Subtract the two sets of ranks to get the difference d. # Square the values of d. # Add the squared values of d to get Sigma d2. # Use the formula Rs = 1-(6Sigma d2/n3-n) where n is the number of ranks you have. # If the Rs value... ... is -1, there is a perfect negative correlation. ...falls between -1 and -0.5, there is a strong negative correlation. ...falls between -0.5 and 0, there is a weak negative correlation. ... is 0, there is no correlation ...falls between 0 and 0.5, there is a weak positive correlation. ...falls between 0.5 and 1, there is a strong positive correlation ...is 1, there is a perfect positive correlation between the 2 sets of data. # If the Rs value is 0, state that null hypothesis is accepted. Otherwise, say it is rejected. (sourced from http://www.revision-notes.co.uk/revision/181.html)



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How do you calculate Spearman's rank correlation? - Answers

https://math.answers.com/algebra/How_do_you_calculate_Spearman's_rank_correlation

# State the null hypothesis i.e. "There is no relationship between the two sets of data." # Rank both sets of data from the highest to the lowest. Make sure to check for tied ranks. # Subtract the two sets of ranks to get the difference d. # Square the values of d. # Add the squared values of d to get Sigma d2. # Use the formula Rs = 1-(6Sigma d2/n3-n) where n is the number of ranks you have. # If the Rs value... ... is -1, there is a perfect negative correlation. ...falls between -1 and -0.5, there is a strong negative correlation. ...falls between -0.5 and 0, there is a weak negative correlation. ... is 0, there is no correlation ...falls between 0 and 0.5, there is a weak positive correlation. ...falls between 0.5 and 1, there is a strong positive correlation ...is 1, there is a perfect positive correlation between the 2 sets of data. # If the Rs value is 0, state that null hypothesis is accepted. Otherwise, say it is rejected. (sourced from http://www.revision-notes.co.uk/revision/181.html)



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https://math.answers.com/algebra/How_do_you_calculate_Spearman's_rank_correlation

How do you calculate Spearman's rank correlation? - Answers

# State the null hypothesis i.e. "There is no relationship between the two sets of data." # Rank both sets of data from the highest to the lowest. Make sure to check for tied ranks. # Subtract the two sets of ranks to get the difference d. # Square the values of d. # Add the squared values of d to get Sigma d2. # Use the formula Rs = 1-(6Sigma d2/n3-n) where n is the number of ranks you have. # If the Rs value... ... is -1, there is a perfect negative correlation. ...falls between -1 and -0.5, there is a strong negative correlation. ...falls between -0.5 and 0, there is a weak negative correlation. ... is 0, there is no correlation ...falls between 0 and 0.5, there is a weak positive correlation. ...falls between 0.5 and 1, there is a strong positive correlation ...is 1, there is a perfect positive correlation between the 2 sets of data. # If the Rs value is 0, state that null hypothesis is accepted. Otherwise, say it is rejected. (sourced from http://www.revision-notes.co.uk/revision/181.html)

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      # State the null hypothesis i.e. "There is no relationship between the two sets of data." # Rank both sets of data from the highest to the lowest. Make sure to check for tied ranks. # Subtract the two sets of ranks to get the difference d. # Square the values of d. # Add the squared values of d to get Sigma d2. # Use the formula Rs = 1-(6Sigma d2/n3-n) where n is the number of ranks you have. # If the Rs value... ... is -1, there is a perfect negative correlation. ...falls between -1 and -0.5, there is a strong negative correlation. ...falls between -0.5 and 0, there is a weak negative correlation. ... is 0, there is no correlation ...falls between 0 and 0.5, there is a weak positive correlation. ...falls between 0.5 and 1, there is a strong positive correlation ...is 1, there is a perfect positive correlation between the 2 sets of data. # If the Rs value is 0, state that null hypothesis is accepted. Otherwise, say it is rejected. (sourced from http://www.revision-notes.co.uk/revision/181.html)

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