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How do you divide radical expressions? - Answers

By applying the conjugate. e.g. 6 / sqrt(2) = (6sqrt(2)) / (sqrt(2)*sqrt(2)) => (6sqrt(2)/ 2=> 3sqrt(2) The answer. Or a more complex calculation. ( 6 - sqrt(5)) / (2 - sqrt(3)) The conjugate is 2 + sqrt(3) ; Apply top and bottom. (6 - sqrt(5))(2 + sqrt(3)) / (2 - sqrt(5))(2 + sqrt(5)) We now use FOIL (Like multiplying two brackets together) . (12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / (4 - 2sqrt(5) + 2 sqrt(5) - 5) ( 12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / ( - 1) -12 + 2sqrt(5) - 6qrt3) + sqrt(15) This cannot be taken any further!!!! Hope that helps with division of radicals.



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How do you divide radical expressions? - Answers

https://math.answers.com/algebra/How_do_you_divide_radical_expressions

By applying the conjugate. e.g. 6 / sqrt(2) = (6sqrt(2)) / (sqrt(2)*sqrt(2)) => (6sqrt(2)/ 2=> 3sqrt(2) The answer. Or a more complex calculation. ( 6 - sqrt(5)) / (2 - sqrt(3)) The conjugate is 2 + sqrt(3) ; Apply top and bottom. (6 - sqrt(5))(2 + sqrt(3)) / (2 - sqrt(5))(2 + sqrt(5)) We now use FOIL (Like multiplying two brackets together) . (12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / (4 - 2sqrt(5) + 2 sqrt(5) - 5) ( 12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / ( - 1) -12 + 2sqrt(5) - 6qrt3) + sqrt(15) This cannot be taken any further!!!! Hope that helps with division of radicals.



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https://math.answers.com/algebra/How_do_you_divide_radical_expressions

How do you divide radical expressions? - Answers

By applying the conjugate. e.g. 6 / sqrt(2) = (6sqrt(2)) / (sqrt(2)*sqrt(2)) => (6sqrt(2)/ 2=> 3sqrt(2) The answer. Or a more complex calculation. ( 6 - sqrt(5)) / (2 - sqrt(3)) The conjugate is 2 + sqrt(3) ; Apply top and bottom. (6 - sqrt(5))(2 + sqrt(3)) / (2 - sqrt(5))(2 + sqrt(5)) We now use FOIL (Like multiplying two brackets together) . (12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / (4 - 2sqrt(5) + 2 sqrt(5) - 5) ( 12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / ( - 1) -12 + 2sqrt(5) - 6qrt3) + sqrt(15) This cannot be taken any further!!!! Hope that helps with division of radicals.

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      By applying the conjugate. e.g. 6 / sqrt(2) = (6sqrt(2)) / (sqrt(2)*sqrt(2)) => (6sqrt(2)/ 2=> 3sqrt(2) The answer. Or a more complex calculation. ( 6 - sqrt(5)) / (2 - sqrt(3)) The conjugate is 2 + sqrt(3) ; Apply top and bottom. (6 - sqrt(5))(2 + sqrt(3)) / (2 - sqrt(5))(2 + sqrt(5)) We now use FOIL (Like multiplying two brackets together) . (12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / (4 - 2sqrt(5) + 2 sqrt(5) - 5) ( 12 -2sqrt(5) + 6 sqrt(3) - sqrt(15)) / ( - 1) -12 + 2sqrt(5) - 6qrt3) + sqrt(15) This cannot be taken any further!!!! Hope that helps with division of radicals.

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